When sodium hydrogencarbonate is heated to 112 degress celsius it decomposes and the gas, carbon dioxide, is given off:

2NaHCO3 (s) ---> Na2CO3 (s) + CO2 (g) + H20 (G)

b) i. Calculate the theoretical volume of carbon dioxide produced by the complete decomposition of 1.68g of sodium hydrogencarbonate.

(Take the molar volume of carbon dioxide to be 23 litres/mol)

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Any help with this question would be greatly appreciated, thanks.

**0**

# 2002 - Written Paper - Q12

Started by David3001, May 30 2005 03:02 PM

4 replies to this topic

### #1

Posted 30 May 2005 - 03:02 PM

### #2

Posted 30 May 2005 - 03:12 PM

QUOTE(David3001 @ May 30 2005, 04:02 PM)

When sodium hydrogencarbonate is heated to 112 degress celsius it decomposes and the gas, carbon dioxide, is given off:

2NaHCO3 (s) ---> Na2CO3 (s) + CO2 (g) + H20 (G)

b) i. Calculate the theoretical volume of carbon dioxide produced by the complete decomposition of 1.68g of sodium hydrogencarbonate.

(Take the molar volume of carbon dioxide to be 23 litres/mol)

2NaHCO3 (s) ---> Na2CO3 (s) + CO2 (g) + H20 (G)

b) i. Calculate the theoretical volume of carbon dioxide produced by the complete decomposition of 1.68g of sodium hydrogencarbonate.

(Take the molar volume of carbon dioxide to be 23 litres/mol)

First of all calculate the no. of moles of sodium hydrogencarbonate:

= 1.68/84

=

**0.02 moles**

Since there is a 2 : 1 ratio between 2NaHCO

_{3}and CO

_{2}, the no. of moles of CO

_{2}is:

**0.01 moles**

Now we can find the Volume, by using this relationship:

Volume = Molar Volume * no. of moles

= 23 * 0.01

= 230cm

^{3}

Volume =

**230cm**

^{3}
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### #3

Posted 30 May 2005 - 03:15 PM

my god that was the easiest exam ever

100%

100%

User Banned.

### #4

Posted 30 May 2005 - 03:16 PM

QUOTE(TheMesiter @ May 30 2005, 04:15 PM)

The exams tomorrow.

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### #5

Posted 30 May 2005 - 03:44 PM

Thanks

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